java Lambda expressions Method References

Method References

You use  lambda expressions  to create anonymous methods. Sometimes, however, a lambda expression does nothing but call an existing method. In those cases, it's often clearer to refer to the existing method by name. Method references enable you to do this; they are compact紧凑简介, easy-to-read lambda expressions for methods that already have a name.

Consider again the Person class discussed in the section Lambda Expressions:

public class Person {

    public enum Sex {
        MALE, FEMALE
    }

    String name;
    LocalDate birthday;
    Sex gender;
    String emailAddress;

    public int getAge() {
        // ...
    }
    
    public Calendar getBirthday() {
        return birthday;
    }    

    public static int compareByAge(Person a, Person b) {
        return a.birthday.compareTo(b.birthday);
    }}

Suppose that the members of your social networking application are contained in an array, and you want to sort the array by age. You could use the following code (find the code excerpts described in this section in the example MethodReferencesTest):

public class MethodReferencesTest {

	// The method transferElements copies elements from one collection to
    // another
	public static <T, SOURCE extends Collection<T> ,DEST extends Collection<T>> DEST transferElements(
			SOURCE sourceCollection, Supplier<DEST> collectionFactory){
		DEST result = collectionFactory.get();
		for(T t : sourceCollection){
			result.add(t);
		}
		return result;
	}
	
	
	public static void main(String[] args) {
		List<Person> roster = Person.createRoster();    
		
		Person[] rosterAsArray = roster.toArray(new Person[roster.size()]);
		
		class PersonAgeComparator implements Comparator<Person> {
	        public int compare(Person a, Person b) {
	            return a.getBirthday().compareTo(b.getBirthday());
	        }
	    }
		// Without method reference
        Arrays.sort(rosterAsArray, new PersonAgeComparator());
		
        // With lambda expression
        Arrays.sort(rosterAsArray,
            (Person a, Person b) -> {
                return a.getBirthday().compareTo(b.getBirthday());
            }
        );
        
        // With method reference
        Arrays.sort(rosterAsArray, Person::compareByAge);
        
        // Reference to an instance method of a particular object
        class ComparisonProvider {
            public int compareByName(Person a,
                Person b) {
                return a.getName().compareTo(b.getName());
            }
        
            public int compareByAge(Person a,
                Person b) {
                return a.getBirthday().compareTo(b.getBirthday());
            }
        }
        ComparisonProvider myComparisonProvider = new ComparisonProvider();
        Arrays.sort(rosterAsArray, myComparisonProvider::compareByName);
        
        // Reference to an instance method  of an arbitrary武断随意 object of a particular特定 type
        String[] stringArray = { "Barbara", "James", "Mary", "John",
            "Patricia", "Robert", "Michael", "Linda" };
        Arrays.sort(stringArray, String::compareToIgnoreCase);
        
        Set<Person> rosterSetLambda = transferElements(roster, () -> { return new HashSet<>(); });
        Set<Person> rosterSet = transferElements(
            roster, HashSet::new);
        System.out.println("Printing rosterSet:");
        rosterSet.stream().forEach(p -> p.printPerson());
	}
}

Person[] rosterAsArray = roster.toArray(new Person[roster.size()]);

class PersonAgeComparator implements Comparator<Person> {
    public int compare(Person a, Person b) {
        return a.getBirthday().compareTo(b.getBirthday());
    }
}
        
Arrays.sort(rosterAsArray, new PersonAgeComparator());

The method signature of this invocation of sort is the following:

static <T> void sort(T[] a, Comparator<? super T> c)

Notice that the interface Comparator is a functional interface. Therefore, you could use a lambda expression instead of defining and then creating a new instance of a class that implements Comparator:

Arrays.sort(rosterAsArray,
    (Person a, Person b) -> {
        return a.getBirthday().compareTo(b.getBirthday());
    }
);

However, this method to compare the birth dates of two Person instances already exists as Person.compareByAge. You can invoke this method instead in the body of the lambda expression:

Arrays.sort(rosterAsArray,
    (a, b) -> Person.compareByAge(a, b)
);

Because this lambda expression invokes an existing method, you can use a method reference instead of a lambda expression:

Arrays.sort(rosterAsArray, Person::compareByAge);

The method reference Person::compareByAge is semantically语意 the same as the lambda expression (a, b) -> Person.compareByAge(a, b). Each has the following characteristics:

  • Its formal parameter list is copied from Comparator<Person>.compare, which is (Person, Person).
  • Its body calls the method Person.compareByAge.

Kinds of Method References

There are four kinds of method references:

Kind Example
Reference to a static method ContainingClass::staticMethodName
Reference to an instance method of a particular object containingObject::instanceMethodName
Reference to an instance method of an arbitrary object of a particular type ContainingType::methodName
Reference to a constructor ClassName::new


Reference to a static method

The method reference Person::compareByAge is a reference to a static method.


Reference to an instance method of a particular object

The following is an example of a reference to an instance method of a particular object:

class ComparisonProvider {
    public int compareByName(Person a, Person b) {
        return a.getName().compareTo(b.getName());
    }
        
    public int compareByAge(Person a, Person b) {
        return a.getBirthday().compareTo(b.getBirthday());
    }
}
ComparisonProvider myComparisonProvider = new ComparisonProvider();
Arrays.sort(rosterAsArray, myComparisonProvider::compareByName);

The method reference myComparisonProvider::compareByName invokes the method compareByName that is part of the object myComparisonProvider. The JRE infers the method type arguments, which in this case are (Person, Person).


Reference to an instance method of an arbitrary object of a particular type

The following is an example of a reference to an instance method of an arbitrary object of a particular type:

String[] stringArray = { "Barbara", "James", "Mary", "John",
    "Patricia", "Robert", "Michael", "Linda" };
Arrays.sort(stringArray, String::compareToIgnoreCase);

The equivalent lambda expression for the method reference String::compareToIgnoreCase would have the formal parameter list (String a, String b), where a and b are arbitrary names used to better describe this example. The method reference would invoke the method a.compareToIgnoreCase(b).


Reference to a constructor

You can reference a constructor in the same way as a static method by using the name new. The following method copies elements from one collection to another:

public static <T, SOURCE extends Collection<T>, DEST extends Collection<T>>
    DEST transferElements(
        SOURCE sourceCollection,
        Supplier<DEST> collectionFactory) {
        
        DEST result = collectionFactory.get();
        for (T t : sourceCollection) {
            result.add(t);
        }
        return result;
}

The functional interface Supplier contains one method get that takes no arguments and returns an object. Consequently, you can invoke the method transferElements with a lambda expression as follows:

Set<Person> rosterSetLambda =
    transferElements(roster, () -> { return new HashSet<>(); });

You can use a constructor reference in place of the lambda expression as follows:

Set<Person> rosterSet = transferElements(roster, HashSet::new);

The Java compiler infers that you want to create a HashSet collection that contains elements of type Person. Alternatively, you can specify this as follows:

Set<Person> rosterSet = transferElements(roster, HashSet<Person>::new);

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转载自blog.csdn.net/H291850336/article/details/51979795
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