LeetCode: 566 Reshape the Matrix

题目：

In MATLAB, there is a very useful function called 'reshape', which can reshape a matrix into a new one with different size but keep its original data.

You're given a matrix represented by a two-dimensional array, and two positive integers r and c representing the row number andcolumn number of the wanted reshaped matrix, respectively.

The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversing order as they were.

If the 'reshape' operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.

Example 1:

Input: 
nums = 
[[1,2],
 [3,4]]
r = 1, c = 4
Output: 
[[1,2,3,4]]
Explanation:
The row-traversing of nums is [1,2,3,4]. The new reshaped matrix is a 1 * 4 matrix, fill it row by row by using the previous list.

Example 2:

Input: 
nums = 
[[1,2],
 [3,4]]
r = 2, c = 4
Output: 
[[1,2],
 [3,4]]
Explanation:
There is no way to reshape a 2 * 2 matrix to a 2 * 4 matrix. So output the original matrix. 

Note:

1. The height and width of the given matrix is in range [1, 100].
2. The given r and c are all positive.

代码：

class Solution {
public:
    vector<vector<int>> matrixReshape(vector<vector<int>>& nums, int r, int c) {
        int row = nums.size();
        if (row == 0)
            return nums;
        int length = nums[0].size();
        vector<vector<int>> result(r, vector<int>(c));
        
        if ((row * length) != (r*c))
            return nums;
        else {
            for (int i = 0; i < r; ++i) {
                for (int j = 0; j < c; ++j) {
                    int k = i * c + j;
                    result[i][j] = nums[k/length][k%length];
                }
            }
            return result;
        }
    }
};

注意：二维数组定义是 vector<vector<int>> result(r, vector<int>(c));

　　　然后才可以赋值，否则会报错：

Line 22: no matching function for call to 'std::vector<std::vector<int> >::push_back(__gnu_cxx::__alloc_traits<std::allocator<int> >::value_type&)'