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sql：
SELECT @s :=@s + 1 as 'index', DATE(DATE_SUB(CURRENT_DATE, INTERVAL @s DAY)) AS 'date' FROM mysql.help_topic,(SELECT @s := -1) temp WHERE @s < 7 ORDER BY 'date' ;
结果：
| index |
date |
| 0 |
2019-03-06 |
| 1 |
2019-03-05 |
| 2 |
2019-03-04 |
| 3 |
2019-03-03 |
| 4 |
2019-03-02 |
| 5 |
2019-03-01 |
| 6 |
2019-02-28 |
| 7 |
2019-02-27 |