题目描述:
代码如下:
//7-20
#include <stdio.h>
int main ( )
{
int n, i, j;
scanf( "%d", &n );
for( i = 1; i <= n; i++ ){
for( j = 1; j <= i; j++ )
printf( "%d*%d=%-4d", j, i, i * j );
printf( "\n" );
}
return 0;
}
题目描述:
代码如下:
//7-20
#include <stdio.h>
int main ( )
{
int n, i, j;
scanf( "%d", &n );
for( i = 1; i <= n; i++ ){
for( j = 1; j <= i; j++ )
printf( "%d*%d=%-4d", j, i, i * j );
printf( "\n" );
}
return 0;
}