Python-剑指offer（15,16）反转链表，合并两个链表

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题目：输入一个链表，反转链表后，输出新链表的表头。

环境：Python2.7.3

# -*- coding:utf-8 -*-
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
class Solution:
    # 返回ListNode
    def ReverseList(self, pHead):
        # write code here
        if not pHead or not pHead.next:
            return pHead
        newHead = None
        while pHead:
            temp = pHead.next
            pHead.next = newHead
            newHead = pHead
            pHead = temp
        return newHead

题目：输入两个单调递增的链表，输出两个链表合成后的链表，当然我们需要合成后的链表满足单调不减规则。

# -*- coding:utf-8 -*-
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
class Solution:
    # 返回合并后列表
    def Merge(self, pHead1, pHead2):
        # write code here
        if not pHead1:
            return pHead2
        if not pHead2:
            return pHead1
        if pHead1.val < pHead2.val:
            pres = pHead1
            pres.next = self.Merge(pHead1.next, pHead2)
        else:
            pres = pHead2
            pres.next = self.Merge(pHead1, pHead2.next)
        return pres