c语言-判断日期

判断日期

下面程序中子函数MonthDay()的功能是将某年的第几天转换为某月某日。程序的运行结果如下：

Please enter year, yearDay:2014,100↙

month = 4, day = 10

程序：

#include    <stdio.h>
void  MonthDay(int year, int yearDay, int *pMonth, int *pDay);
int dayTab[2][13] = {{0,31,28,31,30,31,30,31,31,30,31,30,31},{0,31,29,31,30,31,30,31,31,30,31,30,31}};
 
int main()     
{
    int year, month, day, yearDay;
    printf("Please enter year, yearDay:");
    scanf("%d,%d", &year, &yearDay);
    MonthDay(year, yearDay, &month, &day);
    printf("month = %d, day = %d\n", month, day); 
    return 0;  
}
 
/* 函数功能：对给定的某一年的第几天，计算它是这一年的第几月第几日 */
void  MonthDay(int year, int yearDay, int *pMonth, int *pDay)
{  
    int  i, leap;
    leap = ((year % 4 == 0) && (year % 100 != 0)) || (year % 400 == 0);
     
    for (i=1; yearDay>dayTab[leap][i]; i++)
    {
        yearDay = yearDay - dayTab[leap][i];
    }
    *pMonth = i;        /* 将计算出的月份值赋值给pMonth所指向的变量 */
     
    *pDay = yearDay;   /* 将计算出的日号赋值给pDay所指向的变量 */
}