js获取地址栏中的参数

通过js获取导航栏中的参数:

  请求地址举例:  http://xxxxx.com/index.php?param=value&param1=value1

  function GetRequest() {
            var url = decodeURI(location.search); //获取url中"?"符后的字串
            var theRequest = new Object();
            if (url.indexOf("?") != -1) {
                var str = url.substr(1);
                strs = str.split("&");
                for(var i = 0; i < strs.length; i ++) {
                    theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
                }
            }
            return theRequest;
        }

获取参数的方法:

var json = GetRequest();
//json是获取所有参数的键值对象,可公国console.log(json)查看

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转载自www.cnblogs.com/callmelx/p/10654284.html