利用Python在PI中寻找生日

（1）使用y-cruncher工具得待PI的亿万位的txt文档；

cruncher下载

（2）代码很简单，首先是得到可操作的文档，然后提示用户输入要查找的生日，默认的格式是year-mouth-day，例如94-01-01，先检查输入的生日格式是否正确，要是正确的话就从文档中进行查找，若查找到就返回其存在的个数，从查找的结果来看，本人的生日出现的次数还是挺多的，但是要是查找的8位的生日，就没有那么幸运了。

（3）本程序只能对特定格式的数进行查找，要是想要查找别的数据，稍微的更改下程序就可以了。

import sys
import re

def get_file():
	#get the file to operate
	f = open(r"K:\_\Python\Pi.txt", "r")
	lines = f.read()
	f.close()
	return lines
	
def judge_birthday(number):
	#judge the format of birthday is righy or not
	dir_birthday = {'01':31, "02":28, "03":31, "04":30, 
					"05":31, "06":30, "07":31, "08":31, 
					"09":30, "10":31, "11":30, "12":31
					}
	if len(number) < 8:
		number = '19' + number
	year = int(number[:4])
	mouth = int(number[4:6])
	day = int(number[6:])
	if (year > 2000) or (year < 1900):
		return False
	if (mouth > 12) or (mouth < 1):
		return False
	else:		
		day_correct = dir_birthday[number[4:6]]
		if (year % 400 == 0) or (year % 4 == 0 and year % 100 != 0):
			day_correct += 1
		if (day < 1) or (day > day_correct):
			return False
	return True
	
def search_in_PU(number, lines):
	#search the number of birthday in the PI file
	length = len(re.findall(number, lines))
	if length < 1:
		print("Not found!")
	else:
		print(number + ": " + str(length))
		
if __name__ == "__main__":
	lines = get_file()
	print("Enter the year that you want to search: ")
	number = input()
	flag = judge_birthday(number)
	if flag:
		search_in_PU(number, lines)
	else:
		print("The format of your birthday is not correct!")