Given a binary array, find the maximum number of consecutive 1s in this array.
找出列表中连续‘1’的最大个数。
Example 1:
Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
Note:
- The input array will only contain
0
and1
. - The length of input array is a positive integer and will not exceed 10,000
class Solution:
def findMaxConsecutiveOnes(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
nums = ''.join(str(each) for each in nums)
nums = nums.split('0')
ans = 0
for i in range(len(nums)):
ans = max(ans, len(nums[i]))
return ans
def findMaxConsecutiveOnes(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
nums = ''.join(str(each) for each in nums)
nums = nums.split('0')
ans = 0
for i in range(len(nums)):
ans = max(ans, len(nums[i]))
return ans