Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
大概意思:a+b然后输出带逗号的那种表示方式
#include<iostream>
#include<algorithm>
#include<string>
using namespace std;
int main()
{
int a, b;
cin >> a >> b;
int c = a + b;
string s = to_string(c); //因为有‘-’所以采用字符串来表示
if(s[0] == '-')
{
cout << '-';
s = s.substr(1, s.length() - 1); //如果存在负号,则输出,再将字符串变成绝对值
}
int t = s.length() % 3; //每三位输出一个',',但是要考虑最前面可能不足三位
for (int i = 0; i < t;i++)
{
cout << s[i];
}
string s2 = s.substr(t, s.length() - t);
int g = s2.length()/3;
for (int i = 0; i < g;i++)
{
if(t !=0)
cout << ',' << s2[i * 3] << s2[i * 3 + 1] << s2[i * 3 + 2];
else
{
cout<< s2[i * 3] << s2[i * 3 + 1] << s2[i * 3 + 2];
if(i != g-1)
cout << ',';
}
}
return 0;
}