sql按年、月、日、查询排序

如下表table1:
  日期(exportDate) 数量(amount)
  -------------- -----------
  14-2月 -08 20
  10-3月 -08 2
  14-4月 -08 6
  14-6月 -08 75
  24-10月-09 23
  14-11月-09 45
  04-8月 -10 5
  04-9月 -10 44
  04-10月-10 88

2.按月份分组
  select to_char(exportDate,‘yyyy-mm’),sum(amount) from table1 group by to_char(exportDate,‘yyyy-mm’)
  order by to_char(exportDate,‘yyyy-mm’);
  月份 数量
  -----------------------------
  2008-02 20
  2008-03 2
  2008-04 6
  2008-06 75
  2009-10 23
  2009-11 45
  2010-08 5
  2010-09 44
  2010-10 88


1.按年份分组
  select to_char(exportDate,‘yyyy’),sum(amount) from table1 group by to_char(exportDate,‘yyyy’);
  年份 数量
  -----------------------------
  2009 68
  2010 137
  2008 103


3.按季度分组
  select to_char(exportDate,‘yyyy-Q’),sum(amount) from table1 group by to_char(exportDate,‘yyyy-Q’)
  order by to_char(exportDate,‘yyyy-Q’);
  季度 数量
  ------------------------------
  2008-1 22
  2008-2 81
  2009-4 68
  2010-3 49
  2010-4 88
  4.按周分组
  select to_char(exportDate,‘yyyy-IW’),sum(amount) from table1 group by to_char(exportDate,‘yyyy-IW’)
  order by to_char(exportDate,‘yyyy-IW’);
  周 数量
  ------------------------------
  2008-07 20
  2008-11 2
  2008-16 6
  2008-24 75
  2009-43 23
  2009-46 45
  2010-31 5
  2010-35 44
  2010-40 88
  补充:
  按季度分组还有个比较笨的方法(参考网络资源)
  select to_char(exportDate,‘yyyy’),
  sum(decode(to_char(exportDate,‘mm’),‘01’,amount,‘02’,amount,‘03’,amount,0)) as 第一季,
  sum(decode(to_char(exportDate,‘mm’),‘04’,amount,‘05’,amount,‘06’,amount,0)) as 第二季,
  sum(decode(to_char(exportDate,‘mm’),‘07’,amount,‘08’,amount,‘09’,amount,0)) as 第三季,
  sum(decode(to_char(exportDate,‘mm’),‘10’,amount,‘11’,amount,‘12’,amount,0)) as 第四季
  from table1
  group by to_char(exportDate,‘yyyy’);
  年份 第一季 第二季 第三季 第四季
  --------------------------------------------------
  2009 0 0 0 68
  2010 0 0 49 88
  2008 22 81 0 0

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转载自blog.csdn.net/M983373615/article/details/83858094