面试题:分层打印二叉树

需求:

树的结构

//                1
//           /        \
//         2           3
//       /   \        /  \
//      4     5     6    7

需要按照如下的方式进行打印:

1
23
4567

分析:

本文按照非递归的方式进行打印,其中的关键就是:

1):使用队列保存当前要打印的节点

2):当前层打印完毕后换行

代码:

 public static void printTree(BineryTreeNode root){
        //首先做一个安全的判断
        if(root == null){
            return ;
        }
        //用一个队列存储当前要打印的节点
        Queue<BineryTreeNode> queue = new LinkedList<BineryTreeNode>();
        int current; //当前层还未打印的节点
        int next ; //下一层的节点个数

        queue.add(root);//开始将头节点放入队列
        current = 1 ;
        next = 0 ;
        while (!queue.isEmpty()){//如果当前的队列不为空
            final BineryTreeNode currentNode = queue.poll();//弹出当前队列的值
            System.out.print(currentNode.data + "  ");
            current -- ;

            //打印左子树
            if(currentNode.left != null){
                queue.add(currentNode.left);
                next ++ ;
            }

            //打印右子树
            if(currentNode.right != null){
                queue.add(currentNode.right);
                next ++ ;
            }
            if(current == 0){//如果current为0,说明当前层打印完毕
                System.out.println();//换行
                current = next ;//下一节点没打印的个数就是:左子树 + 右子树
                next = 0 ;//将next至0,从下层开始继续遍历
            }
        }
    }

全部代码:

package demo2;

import jdk.nashorn.internal.ir.BinaryNode;

import java.util.LinkedList;
import java.util.Queue;

/**
 * Created by angel
 */

class BineryTreeNode{
    public int data ;
    public BineryTreeNode left ; //树的左节点
    public BineryTreeNode right ; //树的右节点
    public BineryTreeNode(int data){
        this.data = data ;
    }

    @Override
    public String toString() {
        return "[data" + data + " , left = " + left + " , right = "+ right +"]" ;
    }
}

public class PrintBineryTree {

    public static void main(String[] args) {
        BineryTreeNode node1 = new BineryTreeNode(1);
        BineryTreeNode node2 = new BineryTreeNode(2);
        BineryTreeNode node3 = new BineryTreeNode(3);
        BineryTreeNode node4 = new BineryTreeNode(4);
        BineryTreeNode node5 = new BineryTreeNode(5);
        BineryTreeNode node6 = new BineryTreeNode(6);
        BineryTreeNode node7 = new BineryTreeNode(7);
        node1.left = node2 ;
        node1.right= node3 ;
        node2.left = node4 ;
        node2.right = node5 ;
        node3.left = node6 ;
        node3.right = node7 ;

        printTree(node1);
    }

    public static void printTree(BineryTreeNode root){
        //首先做一个安全的判断
        if(root == null){
            return ;
        }
        //用一个队列存储当前要打印的节点
        Queue<BineryTreeNode> queue = new LinkedList<BineryTreeNode>();
        int current; //当前层还未打印的节点
        int next ; //下一层的节点个数

        queue.add(root);//开始将头节点放入队列
        current = 1 ;
        next = 0 ;
        while (!queue.isEmpty()){//如果当前的队列不为空
            final BineryTreeNode currentNode = queue.poll();//弹出当前队列的值
            System.out.print(currentNode.data + "  ");
            current -- ;

            //打印左子树
            if(currentNode.left != null){
                queue.add(currentNode.left);
                next ++ ;
            }

            //打印右子树
            if(currentNode.right != null){
                queue.add(currentNode.right);
                next ++ ;
            }
            if(current == 0){//如果current为0,说明当前层打印完毕
                System.out.println();//换行
                current = next ;//下一节点没打印的个数就是:左子树 + 右子树
                next = 0 ;//将next至0,从下层开始继续遍历
            }
        }
    }
}

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转载自www.cnblogs.com/niutao/p/10628778.html