每日一题3.16.2

每日一题3.16.2

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解题思路:
现将两个字符串中的大小写字母全部改为小写字母,再依次遍历公共字符串,用临时变量存储,比较出最长的公共字符串
代码实现:

#include <iostream>
#include <string.h>
using namespace std;
#define max(a,b) a > b? a : b
int getCommonStrLength(char *pFirstStr, char *pSecondStr)
{
	int count = 0;
	int tmp = 0;
	int i = 0, j = 0;
	int a;
	if (pFirstStr == NULL || pSecondStr == NULL)
		return 0;
	for (i = 0; i < strlen(pFirstStr); i++)
	{
		for (j = 0; j < strlen(pSecondStr); j++)
		{
			int a = i, b = j;
			while ((pFirstStr[a] == pSecondStr[b]) && a<strlen(pFirstStr) && b<strlen(pSecondStr))
			{
				
				a++;
				b++;
				tmp++;
			}
			count = max(tmp, count);
			tmp = 0;
		}
	}
	
	cout << count;
	return count;

}

int main()
{
	char str1[256];
	char str2[256];
	cin >> str1 >> str2;
	for (unsigned int i = 0; i<strlen(str1); i++)
	{
		str1[i] = tolower(str1[i]);
	}
	for (unsigned int i = 0; i<strlen(str2); i++)
	{
		str2[i] = tolower(str2[i]);
	}
	getCommonStrLength(str1, str2);
	system("pause");
	return 0;



}

参考答案:
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转载自blog.csdn.net/lxb18821659801/article/details/88718272