1039 到底买不买（C语言）

设计思路：

• 利用 ASCII 数组对应珠子的数目

编译器：C (gcc)

#include <stdio.h>

int main()
{
    int beads[128] = {0};
    char ch;
    int i, more = 0, less = 0;
    while((ch = getchar()) != '\n'){
        beads[(int)ch]++;
    }
    while((ch = getchar()) != '\n'){
        beads[(int)ch]--;
    }

    for(i = 0; i < 128; i++){
        if(beads[i] > 0) more += beads[i];
        if(beads[i] < 0) less -= beads[i];
    }

    if(less) printf("No %d\n", less);
    else     printf("Yes %d\n", more);
    return 0;
}