双循环递归匹配路由表

/**
*根据后端返回数据要求，导航栏权限返回的是要展示的所以信息，所以我们只能根据返回的对象去匹配我们的路由表，把没有返回的项再路由表里剔除，然后重新生成路由表
*/

// 此处数据皆为模拟操作，真是数据请结合实际情况获取
data: {
    route: [  // 我们定义好的路由表
        {path:"/",name:"a",hidden:true},
        {path:"/b",name:"b",hidden:true,children:[
            {path:"/b_1",name:"b_1",hidden:true},
            {path:"/b_2",name:"b_2",hidden:true},
        ]},
        {path:"/c",name:"c",hidden:true,children:[
            {path:"/c_1",name:"c_1",hidden:true},
            {path:"/c_2",name:"c_2",hidden:true},
            {path:"/c_3",name:"c_3",hidden:true},
        ]},
        {path:"/d",name:"d",hidden:true},
    ],
    permisRoute: [ // 后端返回的路由表权限
        {name:"a"},
        {name:"b",permission:[
            {name:"b_1"},
        ]},
        {name:"c",permission:[
            {name:"c_1"},
            {name:"c_2"},
        ]},
    ]
},
methods: {
    /**
     * [此处方法应写store里，然后再在beforeEach里去动态添加路由，vue2.0提供了addRoutes方法
     * @param  {[type]} route       [router里面自己定义好的路由表]
     * @param  {[type]} permisRoute [后台返回路由表权限]
     * @return {[type]}             [生成新的路由表]
     */
    filterRoute: function(route,permisRoute) {
        for(let i in permisRoute){
            const name = permisRoute[i].name;
            for(let j in route){
                // 修改hidden，匹配路由表
                if(route[j].name == name){
                    route[j].hidden = false;
                    break;
                }
            }
            if(permisRoute[i].permission){
                const permisRouteChild = permisRoute[i].permission;
                const routeChild = route.filter(itme => {
                    return itme.name == name;
                })
                // 递归路由表
                this.filterRoute(routeChild[0].children,permisRouteChild)
            }
        }
        return route
    }
}