java List 排序 Collections.sort() 对 List 排序

class User {
 String name;
 String age;
 
 public User(String name,String age){
  this.name=name;
  this.age=age;
 }
 public String getAge() {
  return age;
 }
 public void setAge(String age) {
  this.age = age;
 }
 public String getName() {
  return name;
 }
 public void setName(String name) {
  this.name = name;
 } 
}


//具体的比较类,实现Comparator接口

import java.util.Comparator;
import java.util.List;
import java.util.ArrayList;
import java.util.Collections;

public class ComparatorUser implements Comparator{

 public int compare(Object arg0, Object arg1) {
  User user0=(User)arg0;
  User user1=(User)arg1;

   //首先比较年龄,如果年龄相同,则比较名字

  int flag=user0.getAge().compareTo(user1.getAge());
  if(flag==0){
   return user0.getName().compareTo(user1.getName());
  }else{
   return flag;
  }  
 }
 
}




//测试类
public class SortTest {

 
 public static void main(String[] args){
  List userlist=new ArrayList();
  userlist.add(new User("dd","4"));
  userlist.add(new User("aa","1"));
  userlist.add(new User("ee","5"));
  userlist.add(new User("bb","2"));  
  userlist.add(new User("ff","5"));
  userlist.add(new User("cc","3"));
  userlist.add(new User("gg","6"));
  
  ComparatorUser comparator=new ComparatorUser();
  Collections.sort(userlist, comparator);
   
  for (int i=0;i<userlist.size();i++){
   User user_temp=(User)userlist.get(i);
      System.out.println(user_temp.getAge()+","+user_temp.getName()); 
  }
  
 }
}


 //首先年龄排序,如果年龄相同,则按名字排序

结果:
   1, aa
   2, bb
   3, cc
   4, dd
   5, ee                    //注意:同样是5岁的人,则比较名字(ee,ff),然后排序
   5, ff
   6, gg

 第二种

/**
* 根据order对User排序
*/
public class User { //此处无需实现Comparable接口
    private String name;
    private Integer order;
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public Integer getOrder() {
        return order;
    }
    public void setOrder(Integer order) {
        this.order = order;
    }
}


public class Test{
    public static void main(String[] args) {
            User user1 = new User();
			user1.setName("a");
			user1.setOrder(1);
			User user2 = new User();
			user2.setName("b");
			user2.setOrder(2);
			List<User> list = new ArrayList<User>();
			list.add(user2);
			list.add(user1);

			Collections.sort(list,new Comparator<User>(){
				public int compare(User arg0, User arg1) {
					return arg0.getOrder().compareTo(arg1.getOrder());
				}
			});

			for(User u : list){
				System.out.println(u.getName());
			}
    }
}
 

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转载自liyonghui160com.iteye.com/blog/2087059