[python] 将两个列表合并成一个字典 dict(zip())方法

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假设你有如下两个list:

keys = ['name', 'age', 'food']
values = ['Monty', 42, 'spam']

如何转变成:

a_dict = {'name' : 'Monty', 'age' : 42, 'food' : 'spam'}

解决方法:

>>> keys = ['a', 'b', 'c']
>>> values = [1, 2, 3]
>>> dictionary = dict(zip(keys, values))
>>> print(dictionary)
{'a': 1, 'b': 2, 'c': 3}

进阶,如果value是一个多级list呢:

keys= ['id', 'name', 'pwd']
values = [[2, '123', '567'],[3, '456', '899']]

解决方法:

>>> keys= ['id', 'name', 'pwd']
>>> values = [[2, '123', '567'],[3, '456', '899']]
# 先遍历rows里面的值,然后在用zip反转
>>> a = [dict(zip(keys,values)) for row in values] if values else None
>>> print(a)
[{'name': [3, '456', '899'], 'id': [2, '123', '567']}, {'name': [3, '456', '899'], 'id': [2, '123', '567']}]

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转载自blog.csdn.net/zongza/article/details/88075156