[努力努力再努力] 大数据中的面试题

第一道:

	 id    impl(展示)	click(点击)
	 1		1				1
	 1		0				1
	 1		0				0
	 1		1				0
	 2		1				0
	 。。。。
	 求:每个用户的展示和点击数(正常的) , 每个用户的不正常的展示和点击数
	 答:(不正常的是:没展示,就点击了)

第二道:

sql中的left join 和 join
准备数据:
a表
+------+------+
| id   | name |
+------+------+
|    3 | ccc  |
|    2 | bbb  |
|    1 | aaa  |
+------+------+
b表:
+------+------+
| id   | name |
+------+------+
|    1 | aaa  |
|    2 | bbb  |
|    4 | ccc  |
+------+------+

join操作:
mysql> select * from a join b on a.id=b.id;
+------+------+------+------+
| id   | name | id   | name |
+------+------+------+------+
|    1 | aaa  |    1 | aaa  |
|    2 | bbb  |    2 | bbb  |
+------+------+------+------+

left join操作:
mysql> select * from a left join b on a.id=b.id;
+------+------+------+------+
| id   | name | id   | name |
+------+------+------+------+
|    3 | ccc  | NULL | NULL |
|    2 | bbb  |    2 | bbb  |
|    1 | aaa  |    1 | aaa  |
+------+------+------+------+

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转载自blog.csdn.net/qq_42585142/article/details/88288323