矩阵种 路径最大值与最小值

class Solution {
public:
    int minPathSum(vector<vector<int> > &grid) {
        //dp[i][j] 代表到i,j 最小sum值 =min(dp[i-1][j],dp[i][j-1])+grid[i][j]
        size_t m=grid.size();
        if(m<=0){
            return 0;
        }
        size_t n=grid[0].size();
        
        vector<vector<int> > dp(m,vector<int>(n,0));
        
        dp[0][0]=grid[0][0];
        for(int i=1;i<n;++i){
            dp[0][i]=dp[0][i-1]+grid[0][i];
        }
        
        for(int i=1;i<m;++i){
            dp[i][0]=dp[i-1][0]+grid[i][0];
        }
        
        for(int i=1;i<m;++i){
            for(int j=1;j<n;++j){
                dp[i][j]=min(dp[i-1][j],dp[i][j-1])+grid[i][j];
            }
        }
        
        return dp[m-1][n-1];
    }
};

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转载自blog.csdn.net/u010325193/article/details/86370952