Algebra_hy的博客开通庆祝

$$\sqrt{a^2+b^2}$$

$$x = a_{1}^n + a_{2}^n + a_{3}^n$$ $\_{i=1}^{n}a_{i}$ $\sqrt{a^2+b^2}$ $\sqrt{a^2+b^2}$ $x = a_{1}^n + a_{2}^n + a_{3}^n$ $\sum_{i=1}^{n}a_{i}$ $\prod_{i=1}^{n}a_{i}$ $\int^{b}_{a}F'(x)dx= F(x)|^{2}$ $\therefore a_{i}=0$ $\because $

$$\begin{align}\notag \dot{x}&=\mathbf{A}x+\mathbf{B}u\\\\ y&=\begin{bmatrix}1&0\\0&1\end{bmatrix}x+\begin{bmatrix}1&0\\\\0&1\end{bmatrix}u\label{name}\end{align} $$

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转载自www.cnblogs.com/Algebra-hy/p/10380940.html