根据key排序
a = {'a':1, 'c':2, 'b':3} [(k,a[k]) for k in sorted(a.keys())] #返回 [('a', 1), ('b', 3), ('c', 2)]
根据value排序
a = {'a':1, 'c':2, 'b':3} sorted(a.items(), key=lambda d:d[1], reverse = True) #返回list:[('b', 3), ('c', 2), ('a', 1)]
a = {'a':1, 'c':2, 'b':3} [(k,a[k]) for k in sorted(a.keys())] #返回 [('a', 1), ('b', 3), ('c', 2)]
a = {'a':1, 'c':2, 'b':3} sorted(a.items(), key=lambda d:d[1], reverse = True) #返回list:[('b', 3), ('c', 2), ('a', 1)]