Oracle中REGEXP_SUBSTR函数
oralce逗号分割变多行
方法一
select a.* ,
REGEXP_SUBSTR(a.rolecode ,'[^,]+',1,l) AS rolecode
from p_user a,(SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100) b
WHERE l <=LENGTH(a.rolecode) - LENGTH(REPLACE(rolecode,','))+1
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使用函数REGEXP_SUBSTR拆分字符串：
5个参数
第一个是输入的字符串
第二个是正则表达式
第三个是标识从第几个字符开始正则表达式匹配。（默认为1）
第四个是标识第几个匹配组。（默认为1）
第五个是是取值范围：
i：大小写不敏感；
c：大小写敏感；
n：点号 . 不匹配换行符号；
m：多行模式；
x：扩展模式，忽略正则表达式中的空白字符。
SELECT a.*,REGEXP_SUBSTR(servicereqid ,'[^;]+',1,l) AS servicereq
FROM sum_portal_satisfaction a,(SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100) b
WHERE l <=LENGTH(servicereqid) - LENGTH(REPLACE(servicereqid,';'))+1
ORDER BY 1,2;
----SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100; 生成1到100的数据行。
----l <=LENGTH(servicereqid) - LENGTH(REPLACE(servicereqid,';'))+1，注意此处是‘L’并非‘1’，上面的REGEXP_SUBSTR的第四个参数也一样。
---下面为拆分字符串，再进行的行转列
create or replace view v_sum_portal_satisfaction_sr as
select
survey_type,
survey_time,
center_code,
center_name,
city_id,
city_name,
REGEXP_SUBSTR(servicereqid ,'[^;]+',1,l) AS servicereqid,
REGEXP_SUBSTR(servicereqname ,'[^;]+',1,l) AS servicereqname,
sum(decode(survey_value,0, sur_times,null)) giveup_times,--调查值 -1:未处理 0:用户放弃 1:很满意 2.满意 3.对csr不满意 4.对其它不满意
sum(decode(survey_value,1, sur_times,null))vsatis_times,
sum(decode(survey_value,2, sur_times,null))satis_times,
sum(decode(survey_value,3, sur_times,null))ncsr_times,
sum(decode(survey_value,4, sur_times,null))nelse_times,
sum(sur_times) sur_times
FROM sum_portal_satisfaction a,(SELECT LEVEL l FROM DUAL CONNECT BY LEVEL<=100) b
WHERE l <=LENGTH(servicereqid) - LENGTH(REPLACE(servicereqid,';'))+1
group by
subslevelid,
center_code,
center_name,
city_id,
city_name,
survey_type,
survey_time,
servicereqid,
servicereqname,l
方法二:
create table testTable (
id nvarchar2(200) primary key not null ,
content nvarchar2(200) not null
)
insert into testTable values ('4','馆内idx_10馆外idx_11总体idx_12');
select * from table ( CAST (fn_split(('馆内idx_1$馆外idx_2$总体idx_3$') ,'$') as ty_str_split ) )
select * from testtable b left join table (fn_split((content), '$') ) a on 1=1;
--实现split函数
CREATE OR REPLACE TYPE ty_str_split IS TABLE OF VARCHAR2 (4000);
CREATE OR REPLACE FUNCTION fn_split (p_str IN VARCHAR2, p_delimiter IN VARCHAR2)
RETURN ty_str_split
IS
j INT := 0;
i INT := 1;
len INT := 0;
len1 INT := 0;
str VARCHAR2 (4000);
str_split ty_str_split := ty_str_split ();
BEGIN
len := LENGTH (p_str);
len1 := LENGTH (p_delimiter);
WHILE j < len
LOOP
j := INSTR (p_str, p_delimiter, i);
IF j = 0
THEN
j := len;
str := SUBSTR (p_str, i);
str_split.EXTEND;
str_split (str_split.COUNT) := str;
IF i >= len
THEN
EXIT;
END IF;
ELSE
str := SUBSTR (p_str, i, j - i);
i := j + len1;
str_split.EXTEND;
str_split (str_split.COUNT) := str;
END IF;
END LOOP;
RETURN str_split;
END fn_split;
DECLARE
CURSOR c
IS
select * from table ( CAST (fn_split(('馆内idx_1$馆外idx_2$总体idx_3$') ,'$') as ty_str_split ) );
r c%ROWTYPE;
BEGIN
OPEN c;
LOOP
FETCH c INTO r;
EXIT WHEN c%NOTFOUND;
DBMS_OUTPUT.put_line (r.column_value);
END LOOP;
CLOSE c;
END;
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