GZHU18级寒假训练:Gemini's Trial A

For a positive integer n let’s define a function f:
f(n) =  - 1 + 2 - 3 + … + ( - 1)nn
Your task is to calculate f(n) for a given integer n.
Input
The single line contains the positive integer n (1 ≤ n ≤ 1015).
Output
Print f(n) in a single line.
Examples
Input
4
Output
2
Input
5
Output
-3
Note
f(4) =  - 1 + 2 - 3 + 4 = 2
f(5) =  - 1 + 2 - 3 + 4 - 5 =  - 3

#include <iostream>
using namespace std;
int main()
{
     _int64 n;
	while (cin >> n)
	{
		if (n % 2 == 0)
		{
			cout << n / 2 << endl;
		}
		else
			cout << (n - 1) / 2 - n << endl;
	}
}

猜你喜欢

转载自blog.csdn.net/weixin_43981207/article/details/86688122