A + B Again
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 37692 Accepted Submission(s): 15293
Problem Description
There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !
Input
The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.
Output
For each test case,print the sum of A and B in hexadecimal in one line.
Sample Input
+A -A
+1A 12
1A -9
-1A -12
1A -AA
Sample Output
0
2C
11
-2C
-90
没啥好分析的吧…如果用网上查的操作的话很简单……如果不用，自己把小写改大写的话…enmmm感觉很可怕
ac代码
#include
#include
#include
using namespace std;
int main()
{
long long int a,b;
while (cin >>hex>> a >> b)
{
if(a+b>=0)
cout << setiosflags(ios::uppercase) << hex << a+b<<endl;
else cout <<"-"<< setiosflags(ios::uppercase) << hex << -(a+b)<<endl;
}
}