PAT (Advanced Level) Practice A1039 Course List for Student (25 分)(C++)(甲级)(散列、vector)

版权声明:假装有个原创声明……虽然少许博文不属于完全原创,但也是自己辛辛苦苦总结的,转载请注明出处,感谢! https://blog.csdn.net/m0_37454852/article/details/86639035

原题链接:1039 Course List for Student

#include<algorithm>
#include<iostream>
#include<cstdio>
#include <vector>
using namespace std;

const int MAX_M = 26*26*26*10;//学生姓名散列后的最大容量
vector<int> SelectCourse[MAX_M];//存放每个学生所选择的课程的id号

int getID(char name[])//把学生姓名散列为其ID
{
    int ID = 0;
    for(int i=0; i<3; i++)
    {
        ID = ID*26 + (name[i] - 'A');
    }
    ID = ID*10 + (name[3] - '0');
    return ID;
}

int main()
{
    int N, K;
    scanf("%d %d", &N, &K);
    for(int i=0, j; i<K; i++)
    {
        int course_id, stu_num;
        char stu_name[5];
        scanf("%d %d", &course_id, &stu_num);
        for(j=0; j<stu_num; j++)
        {
            scanf("%s", stu_name);
            SelectCourse[getID(stu_name)].push_back(course_id);//存放
        }
    }
    for(int i=0, j; i<N; i++)
    {
        char stu_name[5];
        scanf("%s", stu_name);
        int stu_id = getID(stu_name);
        printf("%s %d", stu_name, SelectCourse[stu_id].size());//先输出名字和所选课程总数
        sort(SelectCourse[stu_id].begin(), SelectCourse[stu_id].end());//排序
        for(j=0; j<SelectCourse[stu_id].size(); j++)
        {
            printf(" %d", SelectCourse[stu_id][j]);//再输出课程号
        }
        printf("\n");
    }
    return 0;
}

猜你喜欢

转载自blog.csdn.net/m0_37454852/article/details/86639035
今日推荐