c语言小作业:输入年月日,判断该日为该年的第几天。

#include<stdio.h>
int main()
{
int m,n,j,sum;
printf(“请输入:年-月-日\n”);
scanf("%d-%d-%d",&m,&n,&j);
if(m%4==0)
switch(n)
{ case 1: sum=j;break;
case 2: sum=31+j;break;
case 3: sum=31+29+j;break;
case 4: sum=31+29+31+j;break;
case 5: sum=31+29+31+30+j;break;
case 6: sum=31+29+31+30+31+j;break;
case 7: sum=31+29+31+30+31+30+j;break;
case 8: sum=31+29+31+30+31+30+31+j;break;
case 9: sum=31+29+31+30+31+30+31+31+j;break;
case 10: sum=31+29+31+30+31+30+31+31+30+j;break;
case 11: sum=31+29+31+30+31+30+31+31+30+31+j;break;
case 12: sum=31+29+31+30+31+30+31+31+30+31+30+j;break; }
else
switch(n)
{ case 1: sum=j;break;
case 2: sum=31+j;break;
case 3: sum=31+28+j;break;
case 4: sum=31+28+31+j;break;
case 5: sum=31+28+31+30+j;break;
case 6: sum=31+28+31+30+31+j;break;
case 7: sum=31+28+31+30+31+30+j;break;
case 8: sum=31+28+31+30+31+30+31+j;break;
case 9: sum=31+28+31+30+31+30+31+31+j;break;
case 10: sum=31+28+31+30+31+30+31+31+30+j;break;
case 11: sum=31+28+31+30+31+30+31+31+30+31+j;break;
case 12: sum=31+28+31+30+31+30+31+31+30+31+30+j;break; }
printf(“这一天是%d年第%d天”,m,sum);
return 0;
}

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转载自blog.csdn.net/weixin_44059597/article/details/86655694