搭建基于maven的springmvc项目

1.可使用maven生成web项目

mvn archetype:generate -DgroupId=com.yyu.cms.web -DartifactId=appcms-web -DarchetypeArtifactId=maven-archetype-webapp -DinteractiveMode=false

参考https://www.cnblogs.com/fishyy/p/10313566.html

2.在appcms-web pom.xml中添加springmvc相关dependency

 <dependency>
      <groupId>org.springframework</groupId>
      <artifactId>spring-core</artifactId>
      <version>4.2.6.RELEASE</version>
    </dependency>
    <dependency>
      <groupId>org.springframework</groupId>
      <artifactId>spring-beans</artifactId>
      <version>4.2.6.RELEASE</version>
    </dependency>
    <dependency>
      <groupId>org.springframework</groupId>
      <artifactId>spring-aspects</artifactId>
      <version>4.2.6.RELEASE</version>
    </dependency>
    <dependency>
      <groupId>org.springframework</groupId>
      <artifactId>spring-webmvc</artifactId>
      <version>4.2.6.RELEASE</version>
    </dependency>
    <dependency>
      <groupId>org.springframework</groupId>
      <artifactId>spring-context</artifactId>
      <version>4.2.6.RELEASE</version>
    </dependency>
View Code

 3.在appcms-web中新建java包

并创建如下controller

4.创建my-dispatcher-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans
       http://www.springframework.org/schema/beans/spring-beans.xsd
       http://www.springframework.org/schema/context
       http://www.springframework.org/schema/context/spring-context.xsd">

    <context:component-scan base-package="com.yyu.cms.web.controller"/>

</beans>
View Code

5.修改web.xml

<!DOCTYPE web-app PUBLIC
 "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
 "http://java.sun.com/dtd/web-app_2_3.dtd" >

<web-app>
  <display-name>SpringMvcApp</display-name>

  <servlet>
      <servlet-name>myDispatcherServlet</servlet-name>
      <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
      <init-param>
          <param-name>contextConfigLocation</param-name>
          <param-value>classpath:my-dispatcher-servlet.xml</param-value>
      </init-param>
      <load-on-startup>1</load-on-startup>
  </servlet>
    <servlet-mapping>
        <servlet-name>myDispatcherServlet</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
</web-app>
View Code

6.打包发布

拷贝appcms-web.war包到tomcat webapp目录修改其名称为yyucms.war

7.运行tomcat,访问yyucms

8.OK!

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转载自www.cnblogs.com/fishyy/p/10315473.html