CodeForces-515A Drazil and Date(语法练习)

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Drazil and Date

time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
Someday, Drazil wanted to go on date with Varda. Drazil and Varda live on Cartesian plane. Drazil’s home is located in point (0, 0) and Varda’s home is located in point (a, b). In each step, he can move in a unit distance in horizontal or vertical direction. In other words, from position (x, y) he can go to positions (x + 1, y), (x - 1, y), (x, y + 1) or (x, y - 1).

Unfortunately, Drazil doesn’t have sense of direction. So he randomly chooses the direction he will go to in each step. He may accidentally return back to his house during his travel. Drazil may even not notice that he has arrived to (a, b) and continue travelling.

Luckily, Drazil arrived to the position (a, b) successfully. Drazil said to Varda: “It took me exactly s steps to travel from my house to yours”. But Varda is confused about his words, she is not sure that it is possible to get from (0, 0) to (a, b) in exactly s steps. Can you find out if it is possible for Varda?

Input
You are given three integers a, b, and s ( - 109 ≤ a, b ≤ 109, 1 ≤ s ≤ 2·109) in a single line.

Output
If you think Drazil made a mistake and it is impossible to take exactly s steps and get from his home to Varda’s home, print “No” (without quotes).

Otherwise, print “Yes”.

Examples
inputCopy
5 5 11
outputCopy
No
inputCopy
10 15 25
outputCopy
Yes
inputCopy
0 5 1
outputCopy
No
inputCopy
0 0 2
outputCopy
Yes
Note
In fourth sample case one possible route is: .

问题简述：

生活在平面直角坐标系上的小D有天想和小V约会，他每次只能朝上下左右四个方向走一步。但他没什么方向感，有时可能会瞎基尔走。现给出小D（0，0）和小V的坐标（a，b）。他和小V说，走到她那花了s步，小V不信，求小D说的是否可能是真的。

问题分析：

最少花了a+b步。其他满足条件的是a+b+x步（x是2的倍数）。

代码实现：

#include<cmath>
#include<cstdio>
#include<iostream>
using namespace std;
int main()
{
    int a,b,s;
    cin>>a>>b>>s;
    a=abs(a);
    b=abs(b);
    if((a+b<s&&(s-a-b)%2==0)||a+b==s) cout<<"Yes";
    else cout<<"No";
}