python weekday()函数

#by 2018.11.11 星期日
import datetime
d=datetime.datetime(2018,11,11)
t=d.weekday()
print(t)

#out:6

import datetime
d=datetime.datetime(2018,11,11)
t=d.weekday()+1
print(t)

#out:7

import datetime
d=datetime.datetime(2018,11,11)
t=d.weekday()
print(t)

#out:6

故+1之后的值才是真实值

#如何将“20181111”格式的日期数据转换为‘星期几’的日期数据
def getWeekday(row):
    if row == 'nan':
        return np.nan
    else:
        return date(int(row[0:4]), int(row[4:6]), int(row[6:8])).weekday() + 1


day1 = "20181111"
day1_1 = getWeekday(day1)
print(day1_1)

#out:7