Description
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 + 7 = 9, return [0, 1].
Solution
1 vector<int> twoSum(vector<int>& nums, int target) { 2 int i,j; 3 4 // Loop for the first item in the array. 5 for ( i=0; i<nums.size(); i++){ 6 // Loop for the second item after the first item. 7 for ( j=i; j<nums.size(); j++){ 8 // Check if the sum equals to target. 9 if( (nums[i] + nums[j]) == target ){ 10 return {i,j}; 11 } 12 } 13 } 14 15 return {-1,-1}; 16 }