[leetcode]795. Number of Subarrays with Bounded Maximum
Analysis
出太阳啦~—— [每天刷题并不难0.0]
We are given an array A of positive integers, and two positive integers L and R (L <= R).
Return the number of (contiguous, non-empty) subarrays such that the value of the maximum array element in that subarray is at least L and at most R.
Explanation:
寻找满足条件的子串
Implement
class Solution {
public:
int numSubarrayBoundedMax(vector<int>& A, int L, int R) {
int len = A.size();
int res = 0;
int tmp = 0;
int j=0;
for(int i=0; i<len; i++){
if(A[i]>=L && A[i]<=R){
res += i-j+1;
tmp = i-j+1;
}
else if(A[i]<L)
res += tmp;
else{
j = i+1;
tmp = 0;
}
}
return res;
}
};