#include <iostream>
#include <map>
#include <string>
#include <stack>
using namespace std;
typedef pair<int,string> mypair;
string transform(long long i)
{
//定义map映射
map<int,string> mymap1;
map<int,string> mymap2;
mymap1.insert(mypair(0,"零"));
mymap1.insert(mypair(1,"壹"));
mymap1.insert(mypair(2,"贰"));
mymap1.insert(mypair(3,"叁"));
mymap1.insert(mypair(4,"肆"));
mymap1.insert(mypair(5,"伍"));
mymap1.insert(mypair(6,"陆"));
mymap1.insert(mypair(7,"柒"));
mymap1.insert(mypair(8,"捌"));
mymap1.insert(mypair(9,"玖"));
mymap2.insert(mypair(1,"拾"));
mymap2.insert(mypair(2,"佰"));
mymap2.insert(mypair(3,"仟"));
mymap2.insert(mypair(4,"万"));
mymap2.insert(mypair(8,"亿"));
int count=-1,j=0,k=0;//count记录位数
int yi=100000000;
int wan=10000;
string result;
stack<int> stak;//用栈实现高位优先
//判断亿位以上
if(i>yi)
{
j=i/yi;
while(j)
{
stak.push(j%10);
++count;
j/=10;
}
while(!stak.empty())
{
k=stak.top();
stak.pop();
while(k==0&&!stak.empty()&&stak.top()==0)//多个零重复只保留一个
{
--count;
stak.pop();
}
if(k==0&&stak.empty()) break;//最后一个零不输出
result+=mymap1[k];
if(count>0&&k!=0)
{
result+=mymap2[count];
--count;
}
else
--count;
}
count=-1;
result+=mymap2[8];//最后加上“亿”位标识符
}
//万位
if(i>wan)
{
j=i%yi;
j=j/wan;
while(j)
{
stak.push(j%10);
++count;
j/=10;
}
while(!stak.empty())
{
k=stak.top();
stak.pop();
while(k==0&&!stak.empty()&&stak.top()==0)
{
--count;
stak.pop();
}
if(k==0&&stak.empty()) break;
result+=mymap1[k];
if(count>0&&k!=0)
{
result+=mymap2[count];
--count;
}
else --count;
}
count=-1;
if(i%yi)
result+=mymap2[4];
}
//万位以下
if(i>0)
{
j=i%wan;
while(j)
{
stak.push(j%10);
++count;
j/=10;
}
while(!stak.empty())
{
k=stak.top();
stak.pop();
while(k==0&&stak.empty()&&stak.top()==0)
{
--count;
stak.pop();
}
if(k==0&&!stak.empty()) break;
result+=mymap1[k];
if(count>0&&k!=0)
{
result+=mymap2[count];
--count;
}
else --count;
}
}
result+="元整";
return result;
}
void main()
{
long long a=0;
string result;
while(a!=-1)
{
cout<<"请输入测试数字(输入-1退出):"<<endl;
cin>>a;
result=transform(a);
cout<<result<<endl;
}
}
c++实现中文大写数字转换
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转载自blog.csdn.net/weixin_40385285/article/details/83270862
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