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参考地址:https://blog.csdn.net/kancy110/article/details/74616909
https://blog.csdn.net/sinat_35626559/article/details/72621695
SELECT
t.QUESTIONNAIRE_ID , listagg(GROUP_NAME,',') within group(order by t.QUESTIONNAIRE_ID)
FROM
T_QMR_QUESTIONNAIRE_GROUP T
JOIN T_NTM_RECEIVER_GROUP G ON G . ID = T .RECEIVER_GROUP_ID
WHERE
T .DELETE_FLAG = 1
AND G .DELETE_FLAG = 1
GROUP BY t.QUESTIONNAIRE_ID