Codility经典算法题之二十七:MinPerimeterRectangle

Task description:

An integer N is given, representing the area of some rectangle.

The area of a rectangle whose sides are of length A and B is A * B, and the perimeter is 2 * (A + B).

The goal is to find the minimal perimeter of any rectangle whose area equals N. The sides of this rectangle should be only integers.

For example, given integer N = 30, rectangles of area 30 are:

  • (1, 30), with a perimeter of 62,
  • (2, 15), with a perimeter of 34,
  • (3, 10), with a perimeter of 26,
  • (5, 6), with a perimeter of 22.

Write a function:

class Solution { public int solution(int N); }

that, given an integer N, returns the minimal perimeter of any rectangle whose area is exactly equal to N.

For example, given an integer N = 30, the function should return 22, as explained above.

Assume that:

  • N is an integer within the range [1..1,000,000,000].

Complexity:

  • expected worst-case time complexity is O(sqrt(N));
  • expected worst-case space complexity is O(1).

Solution:

给定面积的情况下,求最短周长,矩形长和宽都是整数

def solution(n):
    a = 1
    l = []
    while a*a <= n:
        if n%a == 0:
            l.append(2*(a+n/a))
        a += 1
    return int(min(l))

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转载自blog.csdn.net/u010184335/article/details/80050778