sql中跨天（00:00:00）时间差问题的解决

计算2018-12-26 23:58:00至2018-12-27 00:00:00的时间差问题：

SELECT SEC_TO_TIME((TIMESTAMPDIFF(second,'2018-12-26 23:58:00'  ,'2018-12-27 00:00:00' ))) AS 时间差

打印结果：

另一种时间差（秒）：

SELECT TIMESTAMPDIFF(second,'2018-12-26 23:58:00'  ,'2018-12-27 00:00:00' ) AS 时间差

SELECT TIMESTAMPDIFF(minute,'2018-12-26 23:58:00'  ,'2018-12-27 00:00:00' ) AS 时间差

SELECT TIMESTAMPDIFF(HOUR,'2018-12-26 23:58:00'  ,'2018-12-27 02:00:00' ) AS 时间差