jquery的post方式发送AJAX请求

 1 <!DOCTYPE html>
 2 <html>
 3   <head>
 4     <meta http-equiv="content-type" content='text/html;charset=utf-8'>
 5     <script src="https://cdn.bootcss.com/jquery/3.3.1/jquery.min.js" ></script>
 6     <title></title>
 7   </head>
 8   <body>
 9     <script>
10       $.post('./jquery_post.php',{os:'windows',code:'php'},function(data){
11         alert(data.param1 + '------' + data.param2);
12       },'json');
13     </script>
14     <h1 id='h1'></h1>
15   </body>
16 </html>
jquery_post.html
 1 <?php
 2   $os=$_POST['os'];
 3   $code=$_POST['code'];
 4   echo json_encode(
 5     array(
 6       'param1'=>$os,
 7       'param2'=>$code
 8     )
 9   );
10  ?>
jquery_post.php

 1 //判断是否AJAX请求 2 isset($_SERVER['HTTP_X_REQUESTED_WITH'] 

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转载自www.cnblogs.com/t-young1201/p/10231123.html