python编写登录接口

要求：输入用户名密码
　　认证成功显示欢迎信息
　　　输错三次以后锁定
代码如下：
# Author:YK
while(True):
    select=input('请问是注册还是登录')
    if select == '注册':
 register='' #将需要保存的user和password放在register中
 username = input('please input your count...')
 password = input('please input your password...')
 register=register+username+','+password+'\n'
 file1 = open('D:\\study\\code\\study_teach\\day1\\save_user.txt', 'a+',encoding='utf-8')
 #打开保存用户名和密码的文件
 file1.write(register) #写入文件
 file1.close()


 elif select == '登录':
 username = input('please input your count...')
 file2 = open('D:\\study\\code\\study_teach\\day1\\lock.txt', 'r', encoding='utf-8')
 #打开被锁定用户的文件
 count=0
 number=len(file2.readlines()) #获取文件行数
 file2.seek(0, 0) #将鼠标移动到首个字节
 while(count<number):
 count=count+1
 lines = file2.readline().strip('\n') #获取每一行的用户名字符串
 if lines == username: #判断输入的用户名是否和存储的用户名相等
 print('Your count {name} locked'.format(name=username))
 file2.close()
 exit()


 file1 = open('D:\\study\\code\\study_teach\\day1\\save_user.txt', 'r',encoding='utf-8')
 #打开保存用户名和密码的文件
 for i in range(3): #有3次机会输入密码的循环
 password = input('please input your password...')
 count = 0
 number = len(file1.readlines()) #获取文件行数
 file1.seek(0,0)
 while (count < number):
 count=count+1
 line=file1.readline().strip('\n').split(',')
 if line[0] == username and line[1] == password:
 print('Welcom to you submit') #登录成功
 exit() #退出
 if i == 2: #3次均输入错误
 file2 = open('D:\\study\\code\\study_teach\\day1\\lock.txt', 'a+',encoding='utf-8')
 file2.write(username+'\n') #将被锁定的用户名写入被锁文件当中
 file1.close()
 file2.close()
 print('Your count {name} locked'.format(name=username))
 exit()
 else:
 print('输入有错误，请重新输入')
python编写登录接口

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