判断闰年并知道多少天

#include<stdio.h>
int main()
{
int n,y,r,sum=0,j;
//闰年和平年存在数组
int a[2][12]={{31,28,31,30,31,30,31,31,30,31,30,31},{31,29,31,30,31,30,31,31,30,31,30,31}};
printf(“请输入多少年”);
scanf("%d",&n);
printf(“请输入多少月”);
scanf("%d",&y);
printf(“请输入多少日”);
scanf("%d",&r);
//判断闰年

if(y%4==0&&y%100!=0||y%400==0)
j=0;
else
j=1;
sum=sum+a[j][y-1]+r-31;
printf("当前有%d天",sum);
return 0;

}