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导语:我们在使用synchronized(string)同步块时,要注意String常量池带来的例外。
在jvm中具有String常量池缓存的功能。
package com.demo1;
public class Run {
public static void main(String[] args) {
String a = "a";
String b = "a";
System.out.println(a == b);
}
}
打印结果:
true
下面的例子,将说明String常量池带来的例外
package com.demo1;
public class MyObject {
public void print(String stringParam){
try {
synchronized (stringParam) {
while (true) {
System.out.println(Thread.currentThread().getName());
Thread.sleep(1000);
}
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
package com.demo1;
public class ThreadA extends Thread {
private MyObject myObject;
public ThreadA(MyObject myObject) {
this.myObject = myObject;
}
@Override
public void run() {
myObject.print("str");
}
}
package com.demo1;
public class ThreadB extends Thread {
private MyObject myObject;
public ThreadB(MyObject myObject) {
this.myObject = myObject;
}
@Override
public void run() {
myObject.print("str");
}
}
package com.demo1;
public class Run2 {
public static void main(String[] args) {
MyObject myObject = new MyObject();
ThreadA threadA = new ThreadA(myObject);
ThreadB threadB = new ThreadB(myObject);
threadA.setName("a");
threadB.setName("b");
threadA.start();
threadB.start();
}
}
输出结果:
a
a
a
a
a
a
因为ThreadA ThreadB持有相同的锁,导致线程B不能执行。这也就是String 常量池所带来的同步代码块的问题。一般不使用String作为锁对象。例如使用 new Object(),修改代码如下:
package com.demo1;
public class MyObject {
public void print(Object obj){
try {
synchronized (obj) {
while (true) {
System.out.println(Thread.currentThread().getName());
Thread.sleep(1000);
}
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
package com.demo1;
public class ThreadA extends Thread {
private MyObject myObject;
public ThreadA(MyObject myObject) {
this.myObject = myObject;
}
@Override
public void run() {
myObject.print(new Object());
}
}
package com.demo1;
public class ThreadB extends Thread {
private MyObject myObject;
public ThreadB(MyObject myObject) {
this.myObject = myObject;
}
@Override
public void run() {
myObject.print(new Object());
}
}
package com.demo1;
public class Run2 {
public static void main(String[] args) {
MyObject myObject = new MyObject();
ThreadA threadA = new ThreadA(myObject);
ThreadB threadB = new ThreadB(myObject);
threadA.setName("a");
threadB.setName("b");
threadA.start();
threadB.start();
}
}
输出结果:
a
b
a
b
a
b
a
b
a
b
很明显 a,b交替得到cpu资源。