Mysql partition by

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一，看原表

select * from `user`;

二，查询同组年级最大的

select 
username
,SUBSTRING_INDEX( GROUP_CONCAT(age order by age desc) ,',',1) uuid 
from 
(
    select uuid
	,username
	,`password`
	,age
    from `user`
)b 
GROUP BY uuid asc;