python3学习笔记-元祖tupe

#元祖tupe
#元祖被称为只读列表，即数据可以被查询，但不能被修改，所以，字符串的切片操作同样适用于元祖。例：(1,2,3) ("a","b","c")
tu = (1,2,3,'dexter',[2,3,4,'dapeng'],'tom')
print (tu[3])
#dexter
print (tu[0:4])
#(1, 2, 3, 'dexter')
for i in tu:
    print(i)
'''
1
2
3
dexter
[2, 3, 4, 'dapeng']
tom
'''

#儿子不能改，孙子可能可以改
tu[4][3] = tu[4][3].upper()
print(tu)
#(1, 2, 3, 'dexter', [2, 3, 4, 'DAPENG'], 'tom')

#修改元祖报错
#tu[3] = tu[3].capitalize()
#print(tu)

tu[4].append('sd')
print(tu)
#(1, 2, 3, 'dexter', [2, 3, 4, 'DAPENG', 'sd'], 'tom')

s = 'dexter'
s1 = '_'.join(s)
print(s1)
#d_e_x_t_e_r

#列表转换为字符串
li = ['10.88.140.69', '10.88.139.23', '10.88.67.42']
l1 = ','.join(li)
print(l1)
#10.88.140.69,10.88.139.23,10.88.67.42

#字符串转换为列表
str = '10.88.140.69,10.88.139.23,10.88.67.42'
print(str.split(','))
#['10.88.140.69', '10.88.139.23', '10.88.67.42']
for i in str.split(','):
    print(i)
'''
10.88.140.69
10.88.139.23
10.88.67.42
'''

#元祖转换为字符串
li = ('10.88.140.69', '10.88.139.23', '10.88.67.42')
l1 = '+'.join(li)
print(l1)
#10.88.140.69+10.88.139.23+10.88.67.42