python3排序

 1 # 冒泡排序
 2 array = [1, 6, 7, 2, 9, 4]
 3 for i in range(len(array) - 1, 1, -1):
 4     for j in range(0, i):
 5         if array[j] > array[j + 1]:
 6             array[j], array[j + 1] = array[j + 1], array[j]
 7 print(array)
 8 
 9 array.sort()
10 print(array)

1 # 字典排序
2 dict1 = {'a': 2, 'e': 3, 'f': 8, 'd': 4}
3 list1 = sorted(dict1.items(), key=lambda x: x[1])
4 print(list1)

1 import operator
2 # 列表中的字典排序
3 alist = [{"name": "a", "age": 20}, {"name": "b", "age": 30}, {"name": "c", "age": 25}]
4 sorted_x = sorted(alist, key=operator.itemgetter('age'))
5 print(sorted_x)

1 # 统计出现次数
2 a = ['apple', 'banana', 'apple', 'tomato', 'orange', 'apple', 'banana', 'watermeton']
3 print(a.count('apple'))

1 # 合并为字典
2 a = ['a', 'b', 'c', 'd', 'e']
3 b = [1, 2, 3, 4, 5]
4 c = dict(zip(a, b))
5 print(c)