C# -- 冒泡排序

1. C#代码

 1             int[] num = { 3, 5, 7, 1, 2, 13, 9, 4, 6, 11, 22, 44, 33, 14, 43, 41, 5, 868, 476, 34535, 345, 46, 47, 47, 848 };
 2             for (int i = 0; i < num.Length - 1; i++)
 3             {
 4                 for (int j = num.Length - 1; j > i; j--)
 5                 {
 6                     if (num[j] < num[j - 1])
 7                     {
 8                         int temp = num[j];
 9                         num[j] = num[j - 1];
10                         num[j - 1] = temp;
11                     }
12                 }
13             }
14             Console.WriteLine("排序后的数组:");
15             for (int k = 0; k < num.Length; k++)
16             {
17                 Console.Write("{0},", num[k]);
18             }
19 
20             Console.ReadKey()

 2. 运行结果:

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转载自blog.csdn.net/shan1774965666/article/details/83067763