正则表达式之：.*?

s = ‘abababababab’

pattern = re.compile(r'a.*b')

那么检索到的字符串为‘abababababab’，该方法为贪婪匹配，找最长的

pattern = re.compile(r'a.*?b')

加了问号之后默认找最短的

输出就是6个'ab'

# coding=utf-8
import re

s = 'abababababab'
pattern = re.compile(r'a.*b')
print(pattern.findall(s))
pattern = re.compile(r'a.*?b')
print(pattern.findall(s))

['abababababab']
['ab', 'ab', 'ab', 'ab', 'ab', 'ab']