java实现两个有序链表合并为一个有序链表

节点类

public class Node 
{
	private Node next;
	private Integer number;
	Node(Integer number)
	{
		this.number=number;
		next=null;
	}
	Node()
	{
		
	}
	public Node getNext() {
		return next;
	}
	public void setNext(Node next) {
		this.next = next;
	}
	public Integer getNumber() {
		return number;
	}
	public void setNumber(Integer number) {
		this.number = number;
	}
	
}

合并链表
public class SortForLink {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		int[] arr1 = {1,3,6,8,23,34,56,77,90};
		int[] arr2 = {-90,34,55,79,87,98,123,234,567};
		
		Node link1 = new Node();
		Node link2 = new Node();
		Node link3 = new Node();
		
		getLink(arr1,link1);
		getLink(arr2,link2);
		
		mergeLink(link1, link2, link3);
		
		viewLink(link3);
		
		

	}
	
	/**
	 * 构建链表
	 * @param arr
	 * @param link
	 */
	public static void getLink(int[] arr, Node link) {
		
		for(int i = 0; i < arr.length; i++) {
			link.setNumber(arr[i]);
			link.setNext(new Node());
			link = link.getNext();
		}
		
	}
	
	/**
	 * 输出链表
	 * @param link
	 */
	public static void viewLink(Node link) {
		
		while(link.getNumber() != null) {
			System.out.println(link.getNumber());
			link = link.getNext();
		}
	}
	
	/**
	 * 合并链表
	 * @param link1
	 * @param link2
	 * @param link3
	 */
	public static void mergeLink(Node link1, Node link2, Node link3) {
		
		if( (link2.getNumber() != null) && (link1.getNumber() == null || link1.getNumber() >= link2.getNumber()) ) {
			link3.setNumber(link2.getNumber());
			link3.setNext(new Node());
			link2 = link2.getNext();
			link3 = link3.getNext();
			mergeLink(link1, link2, link3);
		}else if( (link1.getNumber() != null) && (link2.getNumber() == null || link2.getNumber() > link1.getNumber()) ) {
			link3.setNumber(link1.getNumber());
			link3.setNext(new Node());
			link1 = link1.getNext();
			link3 = link3.getNext();
			mergeLink(link1, link2, link3);
		}else {
			System.out.println("==没有了，结束啦！==");
		}
	}

}