856. 括号的分数

856. 括号的分数

这道题在网上也有了很多的的解法，我的解题思路主要是利用正则表达式

解题思路：

1. 利用正则表达式

   		regex reg("([\\(]{1})([1]?)([\\)]{1})");

    将所有（）都化为1

2. 创建新的正则表达式

   reg = "([\\(]{1})([0-9]*)([\\)]{1})";
   		regex reg1("([\\(]{1})([1]*)([\\)]{1})");
   		regex reg2("([\\(]{1})([2]*)([\\)]{1})");

   将例如（11111111）或者（22222222）这样的式子计算出来，在程序里，凡是括号内数字之和大于2的统一改变成（num+）这样的形式；

3. 利用最后两个正则表达式

   regex reg3("[\\(]{1}[\\d]{1,}[\\+]{1}[\\)]{1}");
   regex reg4("[\\(]{1}[\\d\\+]{1,}[\\)]{1}");

   就可以处理所有的式子并得出最终的答案

附上测试代码：

class Solution {
public:
	int ans = 0;
	int scoreOfParentheses(string S) 
	{
		
		bool confine = 1;
		string pattern1 = "([\\(]{1})";
		string pattern2 = "([1]{1})";
		string pattern3 = "([\\)]{1})";
		regex reg("([\\(]{1})([1]?)([\\)]{1})");
		smatch m, m1;
		if (regex_search(S, m, reg))
		{
			string temp = m.str(2);
			string pre = m.prefix();
			if (temp.length()==0)
			{
				S = regex_replace(S, reg, "1");
			}
			cout << S << endl;
		}
		disum(S);
		cout << S << endl;
		reg = "([\\(]{1})([0-9]*)([\\)]{1})";
		regex reg1("([\\(]{1})([1]*)([\\)]{1})");
		regex reg2("([\\(]{1})([2]*)([\\)]{1})");
		while (regex_search(S, m, reg))
		{
			string temp = m.str();
			string pre = m.prefix();
			string suf = m.suffix();
			string num = m.str(2);
			string _te;
			auto pos = S.find(temp);
			int re = 0, te = 0, len = 0;
			if (regex_search(temp,reg1))
			{ 
				te = 2 * num.size();
				confine = 0;
			}
			else if (regex_search(temp, reg2))
			{
				te = 2 * 2 * num.size();
				confine = 0;
			}
			else
			{
				te = 2 * stoi(num);
				confine = 1;
			}
			if (confine==0)
			{
				for (int i = pre.length() - 1; i > -1; i--)
				{
					if (pre[i] > 47)
					{
						te += pre[i] - 48;
						re++;
					}
					else
						break;
				}
				for (int i = 0; i < suf.length(); i++)
				{
					if (suf[i] > 47)
					{
						te += suf[i] - 48;
						len++;
					}
					else
						break;
				}
				if (te>2)
				{
					_te = to_string(te) + '+';
				}
				else
				{
					_te = to_string(te);
				}
			}
			else
			{
				for (int i = pre.length() - 1; i > -1; i--)
				{
					if (pre[i] > 47)
					{
						te += (pre[i] - 48)*(pow(10, re));
						re++;
					}
					else
						break;
				}
				for (int i = 0; i < suf.length(); i++)
				{
					if (suf[i] > 47)
					{
						te += suf[i] - 48;
						len++;
					}
					else
						break;
				}
				_te = to_string(te) + '+';
			}

			S.replace(pos - re, temp.length() + re + len, _te);
			cout << S << endl;
		}
		regex reg3("[\\(]{1}[\\d]{1,}[\\+]{1}[\\)]{1}");
		while (regex_search(S,m,reg3))
		{
			string temp = m.str();
			string pre = m.prefix();
			string suf = m.suffix();
			string num;
			for (int i = 0; i < m.str().length(); i++)
			{
				if (m.str()[i] > 47 && m.str()[i] < 58)
				{
					num += m.str()[i];
				}
			}
			string _te;
			auto pos = S.find(temp);
			int re = 0, te = 0, len = 0;

			te = 2 * stoi(num);
			for (int i = pre.length() - 1; i > -1; i--)
			{
				if (pre[i] > 47)
				{
					te += (pre[i] - 48)*(pow(10, re));
					re++;
				}
				else
					break;
			}
			//for (int i = 0; i < suf.length(); i++)
			//{
			//	if (suf[i] > 47)
			//	{
			//		te += suf[i] - 48;
			//		len++;
			//	}
			//	else
			//		break;
			//}
			_te = to_string(te) + '+';

			S.replace(pos - re, temp.length() + re + len , _te);
			cout << S << endl;
		}
		int time = 0;
		
		regex reg4("[\\(]{1}[\\d\\+]{1,}[\\)]{1}");
		while(regex_search(S, m, reg4))
		{
			int t_num = 0;
			string temp = m.str();
			string pre = m.prefix();
			string suf = m.suffix();
			for (int i = temp.length()-1; i >-1; i--)
			{
				if (temp[i] > 47 && temp[i] < 58)
				{
					t_num += (temp[i] - 48)*(pow(10, time));
					time++;
				}
				else if (temp[i] == '+')
					time = 0;
			}
			string _te;
			auto pos = S.find(temp);
			int re = 0, te = 0, len = 0;

			te = 2 * t_num;
			time = 0;
			for (int i = pre.length() - 1; i > -1; i--)
			{
				if (pre[i] > 47)
				{
					te += (pre[i] - 48)*(pow(10, time));
					re++;
					time++;
				}
				else if (pre[i]=='+')
				{
					 time= 0;
					 re++;
				}
				else
					break;
			}
			_te = to_string(te) + '+';

			S.replace(pos - re, temp.length() + re + len, _te);
			cout << S << endl;
			time = 0;
		}


		for (int i = S.length()-1; i >-1; i--)
		{
			if (S[i] > 47 && S[i] < 58)
			{
				ans += (S[i] - 48)*(pow(10, time));
				time++;
			}
			else if (S[i] == '+')
				time = 0;
		}
		return ans;

	}
	int num(string temp)
	{
		int te = 0;
		for (int i = 0; i < temp.length(); i++)
		{
			te += temp[i] - 48;
		}
		return te;
	}
	void disum(string &s)
	{
		regex reg("[0-9]{2,}");
		smatch m;
		string ss;
		while  (regex_search(s, m, reg))
		{
			string temp = m.str();
			auto pos = s.find(temp);
			int te = num(temp);
			
			s.replace(pos, temp.length(), to_string(te));
			if (to_string(te).size() > 1)
			{
				auto save = s.find(to_string(te));
				ans += te;
				//ss += s.substr(0, pos + to_string(te).size());
				s.erase(0, pos + to_string(te).size());
			}
		}
		//s = ss + s;
	}
};