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输入一个含有空格的英文句子,反转句子中的单词顺序。
比如输入“I like to listen to music in my sparetime.”,输出"sparetime. my in music to listen to like I"这样子……
我的实现思路是:
(1)找到空格的位置,将它们存到一个数组中
(2)以空格为界限,反转每个单词
(3)整体反转整个英文句子
具体的代码如下:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define MAXSPACENUM 100
void ReverseString(char *s, int from, int to);
void WordsRotate(int [], int , char *);
int FindSpace(int [], char *);
int main()
{
char s[] = "I like to listen music in my sparetime.";
int space[MAXSPACENUM], i = MAXSPACENUM;
while(i--) //将space数组元素初始化为-1
space[i] = -1;
int spaceNum = FindSpace(space,s); //寻找句子中有几个空格,返回结果
//假设所输入的字符串均含有空格
printf("空格个数是:%d个。",spaceNum); //我就看下对不对
printf("它们所在的位置是:");
for(i = 0; i < spaceNum; i++)
printf(" %d",space[i]);
printf("\n");
WordsRotate(space,spaceNum,s);
printf("%s\n",s);
return 0;
}
void ReverseString(char *s, int from, int to)
{
while(from < to)
{
char first = s[from];
s[from++] = s[to];
s[to--] = first;
}
}
void WordsRotate(int space[],int spaceNum, char *s)
{
int length = strlen(s); //保存字符串长度
int i;
for(i = 0; i <= spaceNum; i++) //每一次反转之后都输出整个字符串,好理解些
{
if(i == 0)
{
ReverseString(s,0,space[0]-1);
printf("%s\n",s);
}
else if(i == spaceNum)
{
ReverseString(s,space[i-1]+1,length-1);
printf("%s\n",s);
}
else
{
ReverseString(s,space[i-1]+1,space[i]-1);
printf("%s\n",s);
}
}
ReverseString(s,0,length-1);
}
//返回空格的个数
int FindSpace(int space[], char *s)
{
int length = strlen(s);
int i = 0, j;
for(j = 0; j < length; j++)
{
if( s[j] == ' ')
{
space[i] = j;
i++;
}
}
return i;
}