PHP最基础的连接数据库搜索

<?php
	$servername = "localhost";
	$username = "root";
	$password = "root";
	$dbname = "test";
	$MYNAME=$_GET["myname"];//接收get传递的值
	 
	// 创建连接
	$conn = new mysqli($servername, $username, $password, $dbname);
	 
	// 检测连接
	if ($conn->connect_error) {
	    die("连接失败: " . $conn->connect_error);
	} 
//	header("Content-Type:text/html;charset=utf-8");
//	echo "连接成功<br>";
//	echo $MYNAME;  //将值通过ajax get发送到php页面
	$sql = "SELECT id, name, age FROM tables";
//  $sql = "SELECT * FROM tables WHERE name='$MYNAME'"; //查询语句
	$result = mysqli_query($conn, $sql);
	$arr=array(); //开始转换
	while ($row = mysqli_fetch_assoc($result)) {  //从结果集中取得一行作为关联数组
	    $arr[] = $row;
	   }
	echo json_encode($arr,JSON_UNESCAPED_UNICODE);
	//json_encode是转换成json字符串       第二个参数是解决中文乱码问题
		 
	mysqli_close($conn);
?>

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转载自blog.csdn.net/qq_41619567/article/details/84629302