LeetCode-easy-Reverse Integer

题目来源:https://leetcode.com/problems/reverse-integer/description/
想到的两点:
第一整数如何变成字符
第二如何把数字翻转

number = input('请输入一个整数')
if number < 0:
    number = list(str(number))
    number.pop(0)
    number.reverse()
    print int('-'+''.join(number))
elif number >0:
    if number > 2*31-1:
       number = 0
    else:
       number = list(str(number))
       number.reverse()
       print int(''.join(number))

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转载自blog.csdn.net/u011644858/article/details/79166483