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文章目录
1. 题目描述:
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
Example:
Input: 1->2->4, 1->3->4
Output: 1->1->2->3->4->4
2. 思路分析:
题目的意思是合并2个有序的链表。
思路是用2个指针分别指向2个链表,比较2个节点,将较小的节点放入结果链表中并且指针后移。
3. Java代码:
源代码
:见我GiHub主页
代码:
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
if (l1 == null) {
return l2;
}
if (l2 == null) {
return l1;
}
ListNode result = new ListNode(0);
ListNode cur = result;
while (l1 != null && l2 != null) {
if (l1.val < l2.val) {
cur.next = l1;
l1 = l1.next;
} else {
cur.next = l2;
l2 = l2.next;
}
cur = cur.next;
}
if (l1 != null) {
cur.next = l1;
}
if (l2 != null) {
cur.next = l2;
}
return result.next;
}